Answer to Question #260830 in C for Mr Z

Question

2. Using the online compiler •

Enter the code

int main(int argc, char *argv[]) {
	
	byte_t first_byte = 128;
	byte_t second_byte = 1;
	int    shift;
	
	printf("Enter the number of left/right shifts: ");
	scanf("%d", &shift);
	printf("\n\n");
	
	// Right-shift first_byte
	first_byte = first_byte >> shift;
	
	// Left-shift second byte
	// This is the equivalent of second_byte = second_byte << shift; 
	second_byte <<= shift;		
	
	// Display the results
	printf("128 >> %d = %d\n", shift, first_byte);
	printf("1 << %d = %d\n", shift, second_byte);
	
	system("pause");
	return 0;
}

You will be prompted to enter a value for the number of shifts. Initially enter the value of zero

Repeat the previous two steps with values of 1, 2, 3, 4, 5, 6, 7 and 8

Answer 1

#include<stdio.h>
int main(int argc, char *argv[]) {
	int first_byte = 128;
	int second_byte = 1;
	int shift;
	printf("Enter the number of left/right shifts: ");
	scanf("%d", &shift);
	printf("\n\n");
	first_byte = first_byte >> shift;
	second_byte <<= shift;		
	printf("128 >> %d = %d\n", shift, first_byte);
	printf("1 << %d = %d\n", shift, second_byte);
	system("pause");
	return 0;
}

Output

0 128>>0=128

1<<0=1

1 128>>1=64

1<<1=2

2 128>>2=32

1<<2=4

3 128>>3=16

1<<3=8

4 128>>4=8

1<<4=16

5 128>>5=4

1<<5=32

6 128>>6=2

1<<6=64

7 128>>7=1

1<<7=128

8 128>>8=0

1<<8=2 56