Write a function that converts a mathematical expression containing parentheses from infix form to postfix form. The function should take pointers to both source infix array and destination postfix array as arguments. You may assume that the maximum array size is fixed. The infix expression will contain multi-digit positive integers only. The function must first check if the brackets in the expression are balanced. The function prototype is given below:
void infixToPostfix(char * src, char * dst);
#include<stdio.h>
#include<stdlib.h> /* for exit() */
#include<ctype.h> /* for isdigit(char ) */
#include<string.h>
#define SIZE 100
/* declared here as global variable because stack[]
* is used by more than one fucntions */
char stack[SIZE];
int top = -1;
/* define push operation */
void push(char item)
{
if(top >= SIZE-1)
{
printf("\nStack Overflow.");
}
else
{
top = top+1;
stack[top] = item;
}
}
/* define pop operation */
char pop()
{
char item ;
if(top <0)
{
printf("stack under flow: invalid infix expression");
getchar();
/* underflow may occur for invalid expression */
/* where ( and ) are not matched */
exit(1);
}
else
{
item = stack[top];
top = top-1;
return(item);
}
}
/* define function that is used to determine whether any symbol is operator or not
(that is symbol is operand)
* this fucntion returns 1 if symbol is opreator else return 0 */
int is_operator(char symbol)
{
if(symbol == '^' || symbol == '*' || symbol == '/' || symbol == '+' || symbol =='-')
{
return 1;
}
else
{
return 0;
}
}
/* define fucntion that is used to assign precendence to operator.
* Here ^ denotes exponent operator.
* In this fucntion we assume that higher integer value
* means higher precendence */
int precedence(char symbol)
{
if(symbol == '^')/* exponent operator, highest precedence*/
{
return(3);
}
else if(symbol == '*' || symbol == '/')
{
return(2);
}
else if(symbol == '+' || symbol == '-') /* lowest precedence */
{
return(1);
}
else
{
return(0);
}
}
void InfixToPostfix(char infix_exp[], char postfix_exp[])
{
int i, j;
char item;
char x;
push('('); /* push '(' onto stack */
strcat(infix_exp,")"); /* add ')' to infix expression */
i=0;
j=0;
item=infix_exp[i]; /* initialize before loop*/
while(item != '\0') /* run loop till end of infix expression */
{
if(item == '(')
{
push(item);
}
else if( isdigit(item) || isalpha(item))
{
postfix_exp[j] = item; /* add operand symbol to postfix expr */
j++;
}
else if(is_operator(item) == 1) /* means symbol is operator */
{
x=pop();
while(is_operator(x) == 1 && precedence(x)>= precedence(item))
{
postfix_exp[j] = x; /* so pop all higher precendence operator and */
j++;
x = pop(); /* add them to postfix expresion */
}
push(x);
/* because just above while loop will terminate we have
oppped one extra item
for which condition fails and loop terminates, so that one*/
push(item); /* push current oprerator symbol onto stack */
}
else if(item == ')') /* if current symbol is ')' then */
{
x = pop(); /* pop and keep popping until */
while(x != '(') /* '(' encounterd */
{
postfix_exp[j] = x;
j++;
x = pop();
}
}
else
{ /* if current symbol is neither operand not '(' nor ')' and nor
operator */
printf("\nInvalid infix Expression.\n"); /* the it is illegeal symbol */
getchar();
exit(1);
}
i++;
item = infix_exp[i]; /* go to next symbol of infix expression */
} /* while loop ends here */
if(top>0)
{
printf("\nInvalid infix Expression.\n"); /* the it is illegeal symbol */
getchar();
exit(1);
}
if(top>0)
{
printf("\nInvalid infix Expression.\n"); /* the it is illegeal symbol */
getchar();
exit(1);
}
postfix_exp[j] = '\0'; /* add sentinel else puts() fucntion */
/* will print entire postfix[] array upto SIZE */
}
/* main function begins */
int main()
{
char infix[SIZE], postfix[SIZE]; /* declare infix string and postfix string */
/* why we asked the user to enter infix expression
* in parentheses ( )
* What changes are required in porgram to
* get rid of this restriction since it is not
* in algorithm
* */
printf("ASSUMPTION: The infix expression contains single letter variables and single digit constants only.\n");
printf("\nEnter Infix expression : ");
gets(infix);
InfixToPostfix(infix,postfix); /* call to convert */
printf("Postfix Expression: ");
puts(postfix); /* print postfix expression */
return 0;
}
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