Answer to Question #217497 in C for Mohammed Ashiq

Question

Develop a C program to perform z=x-y where x=x+x2 , y=1+y.

Answer 1

#include <stdio.h>
#include <ctype.h>
#include <string.h>




int main() {


	float x=0;
	float y=0;
	float z;
	
	printf("Enter x: ");
	scanf("%f",&x);
	printf("Enter y: ");
	scanf("%f",&y);
	x=x+x*x;
	y=1+y;
	z=x-y;


	printf("z = %.2f\n\n",z);
	getchar();
	getchar();
	return 0;
}