Answer to Question #209848 in C for Pragadees

Question

The address of memory location num1 and num2 are passed to function and the pointers *a and *b accept those values. So, the pointer a and b points to address of num1 and num2 respectively. When, the value of pointer is changed, the value in memory location also changed correspondingly. Write a program to swap the values in num1 and num2 using *a and *b. Use + and - operator for swapping

Runtime Input :

5

6

8

Output :

5

Answer 1

#include <stdio.h>
void swapping_numbers(int *a,int *b);
int main(){
	//Initializing num1 to 100 and num2 to 90
  int num1=100,num2=90;
   printf("Before swapping\n");
    printf("The first number is:  %d\n",num1);
  printf("The second number is:  %d\n",num2);
  swapping_numbers(&num1,&num2); 
   printf("After swapping\n");
  printf("The first number is: = %d\n",num1);
  printf("The second number is: = %d\n",num2);
  return 0;
}


void swapping_numbers(int *a,int *b){ 


  *a = *a + *b;
  *b=*a - *b;
  *a=*a - *b;
}