Answer to Question #198271 in C for Pragadees

Question

From a set of array elements, find

the number of occurrences of

each element present in the given

array.

Answer 1

#include <stdio.h>
#include <stdlib.h> 


int main() {
	int numbers[]={5,6,5,8,9,6,5,6,2,1,3,9};
	int usedNumbers[12];
	int i,j;
	int counter = 0;
	int usedNumbersCounter = 0;
	int exists=0;
	for (i=0; i<12; i++){
		counter = 0;
		for (j=0; j<12; j++){
			if (numbers[i] == numbers[j]){
				  counter++;
			}
		}
		exists=0;
		for (j=0; j<12; j++){
			if (numbers[i] == usedNumbers[j]){
				exists=1;
				break;
			}
		}
		if(exists==0){
			printf("The number %d occurrences %d times\n",numbers[i],counter);
			usedNumbers[usedNumbersCounter]=numbers[i];
			usedNumbersCounter++;
		}
	}
            


	getchar();
	getchar();


	return 0;
}