Answer to Question #334326 in C# for chizz

Question

Make a program that will accept an integer and loop for the same number of times as that of the inputted integer and input random integers and add it to the array/list one by one, per line. Afterwards, make your program accept another random integer.

Using that final integer, compare from your array/list if the final integer's value is also present in your current array/list. If so, print "Present"; otherwise, print "None".

 

Start coding now!

Input

The first line contains the size of the array/list.

The next lines contain the integers.

The last line contains an integer to be searched.

5

3

21

2

5

23

2

Output

A line containing a string.

Present

Answer 1

using System;

namespace search
{
    class Program
    {
        public static void Main(string[] args)
        {
            int i, n, search, find;
            Console.Write("Enter size of the array: ");
            n = Convert.ToInt32(Console.ReadLine());
            int [] array = new int[n];
            Console.WriteLine("Enter array:");
            for (i=0; i<n; i++)
                array[i] = Convert.ToInt32(Console.ReadLine());
            find = 0;
            Console.Write("Integer to be searched: ");
            search = Convert.ToInt32(Console.ReadLine());
            for (i=0; i<n; i++)
                if (search == array[i])
                {
                    find = 1;
                    break;
                }
            if (find == 1)
                Console.WriteLine("Present");
            else
                Console.WriteLine("None");
            Console.Write("\nPress any key to continue . . . ");
            Console.ReadKey(true);
        }
    }
}