Assembler Answers

Consider a physical memory of size 2128 KB which is managed by buddies’ scheme. Suppose a set of four programs namely P, Q, R and S demand memory requirement of size 1030KB, 520KB, 70 KB and 130 KB respectively. What would be the size of the memory blocks allocated to these four programs? Is it fair allocation? Justify.

Consider a physical memory of size 2128 KB which is managed by buddies’ scheme. Suppose a set of four programs namely P, Q, R and S demand memory requirement of size 1030KB, 520KB, 70 KB and 130 KB respectively. What would be the size of the memory blocks allocated to these four programs? Is it fair allocation?

Write a MIPS assembly program for the following C program.
int fun (int x, int y);
int recur (int n);
int main(){
printf("input a: ");
scanf("%d", &a);
printf(“input b:”);
scanf("%d", &b);
printf("input c: ");
scanf("%d", &c);
int sum = 0;
sum = a * b + fun( a+1, b-1 ) ;
printf(“ans: %d\n”, sum);
sum += recur(c);
printf(“ans: %d”, sum);
}
int fun ( int x, int y ){
return ( x < y ) ? ( x*y + fun ( x+1, y-1 ) ) : 0 ;
}
int recur (int n){
if(n <= 0)
return 0;
else if (n == 1)
return 1;
else
return recur (n-1) + n;
}

⦁ (Branch Loop, System call)
Please convert C code to assembly code. Write a new assembly file for this part. Must have: one input (positive int)
#++++++++ C code ++++++++++++++++++++++++++
# if ($t0<=0)
# printf("$t0 is %d\n out of boundary, enter a number > 0", $t0);
# else if ($t0 > 15)
# printf("$t0 is %d\n out of boundary, enter a number < 16", $t0);
# else {
# int $t1 = 0;
# for (i=0; i<$t0; i++)
# $t1 += i*i;
# printf("%d\n , $t1);
# }
#++++++++++++++++++++++++++++++++++++++++++

The “Run I/O” may show like this: (input : 13)
please enter a positive int:13
819

The “Run I/O” may show like this: (input : 0)
please enter a positive int:0
$to is out of boundary enter a number>0

The “Run I/O” may show like this: (input : 16)