Answer to Question #259287 in Assembler for Roy

Question

Two code snippets are being presented to you.

1. mov rax, 0x1234567812345678

xor ax, 0x11

mov rdi, ax

call printf

xor rax, 0x11

mov rdi, rax

call printf

2. int x=-2;

unsigned int y = -33;

int z;

z = x + y;

printf(‘‘%u %u %u’’, x,y,z);

printf(‘‘%d %d %d’’, x,y,z);

In both the parts (1) and (2), explain what the two printf function calls

result in. Explain the reasons for any differences in the two cases.

Answer 1

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