Question #85284
1. Prove that n + log n = O(n) by showing that there exists a constant c > 0 such that n + log n ≤ cn.
1
Expert's answer
2019-02-25T08:23:03-0500
n+lognn+log(1+n+n2/2!+n3/3!)n+\log ⁡n\le n+\log⁡(1+n+n^2/2!+n^3/3!)\len+log(en)=n+n=2n,nNn+\log( e^n) =n+n=2n,\quad n\in \mathbb{N}

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