If X is the random variable model ‘the number on a biased die’, and the probability distribution function of X is as shown below,
As here the question is incomplete, so suggested the solution based on the given terms.
Given,
Random variable on biased die = X
p(x) = P(X=x) for all the value of x
Now, the variance of a random variable X
"\\Rightarrow V(X)= E[(X-\\mu)^2]"
For the case of the die toss,
Expected values "E(X)=\\Sigma_{x\\in X}(xP(x))"
Now, for the calculation of variance,
"E(X^2)=\\Sigma x^2 P(x)"
"Var(X)=E(X^2)-E^2(X)"
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