Question

onsider the below algorithm:

for (i=1;i < n;i++)

for (j=1;j < m;j++){

Alloc[i][j]=(2*(i+1)%7)+j%i

}

For n=13 and m=6 answer the following questions

What value Alloc[2][4] will store?

Answer 1

$Alloc[2][4] = (2*(2+1)\%7)+4\%2 = 6$

Answer: $Alloc[2][4] = 6.$