Answer to Question #175721 in Quantum Mechanics for Ava

Question

A 5kg ball is kicked into the air with a speed of 14m/s after 1.42seconds, it reaches the peak of its trajectory calculate the time the change in position The initial velocity the final velocity the average velocity and the acceleration of the object on its way up(before it starts to fall back down) use SI units

Answer 1

$t=1.42~s,$

$v_1=v=14~\frac ms,$

$v_2=0~\frac ms,$

$h=\frac{v^2}{2g},$

$<v>=\frac ht=\frac{v^2}{2gt}=\frac{14^2}{2\cdot 9.8\cdot 1.42}=7~\frac ms,$

$a=-g=-9.8~\frac{m}{s^2}.$