Question #164565

Equation of Quantum hormonic oscillator


1
Expert's answer
2021-02-17T12:06:42-0500

An energy of a classical harmonic oscillator is given by

E=mv22+kx22=p22m+mω2x22E = \frac{mv^2}{2}+\frac{kx^2}{2} = \frac{p^2}{2m}+\frac{m\omega^2 x^2}{2}

Therefore by analogy we construct a hamiltonian of a QHO by associating the corresponding operators to the physical quantities :

H^=22m2x2+12mω2x^2\hat H = -\frac{\hbar^2}{2m} \frac{\partial^2}{\partial x^2} +\frac{1}{2}m \omega^2 \hat x^2 and thus from the Schrodinger equation we get

H^ψ=tψ\hat H \psi = \frac{\partial}{\partial t} \psi

22m2x2ψ(x,t)+12mω2x^2ψ(x,t)=tψ(x,t)-\frac{\hbar^2}{2m} \frac{\partial^2}{\partial x^2} \psi(x,t) +\frac{1}{2}m \omega^2 \hat x^2 \psi(x,t) = \frac{\partial}{\partial t}\psi(x,t) which can be generalized to n-dimensions in the same way as we generalize it in the classical case.



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