Question #88546

A source emits electromagnetic waves of wavelength 3m. One beam reaches the observer
directly and other after reflection from a water surface, travelling 1.5m extra distance
and with intensity reduced to 1/4 as compared to intensity due to the direct beam alone.
The resultant intensity will be
1) (1/4) fold 2) (3/4) fold 3) (5/4) fold 4) (9/4) fold

Expert's answer

The resultant amplitude is equal to


I+14I=32I\sqrt{I}+\sqrt{\frac {1} {4}I}=\frac {3} {2} \sqrt{I}

The resultant intensity is equal to


(32I)2=94I({\frac {3} {2} \sqrt{I}})^2=\frac {9} {4} \sqrt{I}

Answer:

4) (9/4) fold


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