Answer to Question #77778 in Physics for sukhpret

Question

A student drops a water balloon out of a dorm window 13 m above the ground. What is its speed when it hits the ground?

m/s

Answer 1

We can find the speed of the water balloon when it hits the ground from the law of conservation of energy (the potential energy of the water balloon at the height of 13 m above the ground becomes the kinetic energy at ground level):
PE=KE,
mgh=1/2 mv^2,
v=√2gh=√(2∙9.8 m/s^2 ∙13 m)=16 m/s.