Answer to Question #77742 in Physics for Alick wamunyima

Question

A 75Kg block is placed on an inclined plane with an angle of 30o. Find the components of the weight of the block parallel and perpendicular to the incline plane.

Answer 1

a) The component of the weight of the block parallel to the incline plane can be found from the formula:
W_∥=mgsinα=75 kg∙9.8 m/s^2 ∙sin〖30〗^°=367.5 N.
b) The component of the weight of the block perpendicular to the incline plane can be found from the formula:
W_⊥=mgcosα=75 kg∙9.8 m/s^2 ∙cos〖30〗^°=636.5 N.