Question

A race car moves along a circular track at a tangential speed of 35.0 m/s. If the car’s centripetal acceleration is 18.5 m/s2, what is the distance between the car and the center of the track?

Answer 1

Question #77493, Physics / Other

A race car moves along a circular track at a tangential speed of $35.0 \, \text{m/s}$. If the car's centripetal acceleration is $18.5 \, \text{m/s}^2$, what is the distance between the car and the center of the track?

Solution

$$a = \frac{v^2}{r} \Leftrightarrow r = \frac{v^2}{a};$$ $$r = \frac{35.0^2}{18.5} = 66.2 \, \text{m}$$

Answer: 66.2 m.

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