Answer to Question #77492 in Physics for JoseGomez

Question

A girl sits on a tire that is attached to an overhanging tree limb by a rope.The girl’s Father pushes her so her centripetal acceleration is 3.5 m/s . If The length of the rope is 1.5 m, what is the girl’s tangential speed?

Answer 1

We can find the girl’s tangential speed from the definition of the centripetal acceleration:
a_c=v^2/r,
here, a_c is the centripetal acceleration of the girl, v is the girl’s tangential speed and r is radius of the curved path (or the length of the rope).
Then, from this formula we can find the girl’s tangential speed:
v=√(a_c r)=√(3.5 m/s^2 ∙1.5 m)=2.3 m/s.