Question

A car starts with a velocity of 20mls and attained a velocity of 40mls in 12secs. If it maintained this velocity for another 8 seconds after it increased its velocity to 50 mls in a further 5 seconds, After which it is uniformly retarded in another 4 seconds. Using a velocity-time graph calculate the total distance covered by the air

Answer 1

Question #72489, Physics / Other

A car starts with a velocity of 20mls and attained a velocity of 40mls in 12secs. If it maintained this velocity for another 8 seconds after it increased its velocity to 50 mls in a further 5 seconds, After which it is uniformly retarded in another 4 seconds. Using a velocity-time graph calculate the total distance covered by the air

Solution

The distance traveled by the car is equal to the area under the v-t graph.

0-12 s:

$$d _ {1} = 1 2 \times \frac {2 0 + 4 0}{2} = 3 6 0 \mathrm {m}$$

12-20s:

$$d _ {2} = 8 \times 4 0 = 3 2 0 \mathrm {m}$$

20-25s:

$$d _ {3} = 5 \times \frac {4 0 + 5 0}{2} = 2 2 5 \mathrm {m}$$

25-29s:

$$d _ {4} = \frac {4 \times 5 0}{2} = 1 0 0 \mathrm {m}$$ $$d = 360 + 320 + 225 + 100 = 1,005 \text{ m}.$$

Answer: the total distance is 1,005 m.

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