Question

Calculate
the exposure of a section of bone in a case where
the absorbed dose is 2600 J/kg using a value of “f” value for bone
of 160?

Answer 1

Answer on Question #57186, Physics / Other

Calculate the exposure of a section of bone in a case where the absorbed dose is $2600\ \mathrm{J/kg}$ using a value of "f" value for bone of 160?

Solution:

The relation between absorbed dose (D) and exposure (X) is

$$D = f \cdot X$$

where $f$ is conversion factor.

Hence,

$$X = \frac{D}{f} = \frac{2600}{160} = 16.25\ \mathrm{C/kg}$$

Answer: $16.25\ \mathrm{C/kg}$

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