water flow at a rate of 0.25 cm³/min in a horizontal pupe of varying cross sectional areas.Calculate the velocity of the water at a section where the rafius of the pupe is 6cm and (b) at a section where the rafius is 9cm
(a)
"v_1={\\rm 0.25\\: cm^3\/min\/(3.14*(6\\: cm)^2)}\\\\\n\\rm=2.2*10^{-3}\\:cm\/min=0.13\\: cm\/s"(b)
"v_1={\\rm 0.25\\: cm^3\/min\/(3.14*(9\\: cm)^2)}\\\\\n\\rm=9.8*10^{-4}\\:cm\/min=0.059\\: cm\/s"
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