Answer to Question #329321 in Physics for Jay

Question

What is the capacitance of a parallel plate capacitor with metal plates, each of area 1.00 m2, separated by 1.00 mm?

Answer 1

The capacitance is given as follows:

$$C = \dfrac{\epsilon_0A}{d}$$

where $A = 1.00m^2$ is the area of the plate, $d = 1.00mm = 1.00\times 10^{-3}m$ is the distance between plates, and $\epsilon_0 \approx 8.85\times 10^{-12} F/m$ is vacuum permittivity. Thus, obtain:

$$C = \dfrac{8.854\times 10^{-12} F/m\cdot 1.00m^2}{1.00\times 10^{-3}m} =8. 85\times 10^{-9} F$$

Answer. $8. 85\times 10^{-9} F$.