Question #320105

A car P is 300m behind a car B and both are traveling in the same direction at 25ms–¹. Neglecting the length of the cars.


(i) calculate the acceleration of P.


(ii) it's velocity at the moment of passing B.


(iii) The distance it has travelled in 20s.

1
Expert's answer
2022-03-31T11:48:56-0400

(i)

v=v0+atv=v_0+at

aB=ΔvΔt=27.52520=0.125m/s2a_B=\frac{\Delta v}{\Delta t}=\frac{27.5-25}{20}=0.125\:\rm m/s^2dP=dB+300d_P=d_B+300

v0t+aPt2/2=v0t+aBt2/2+300v_0t+a_Pt^2/2=v_0t+a_Bt^2/2+300

aP202/2=0.125202/2+300a_P*20^2/2=0.125*20^2/2+300

aP=1.625  m/s2a_P=1.625\;\rm m/s^2

(ii)

vP=v0+aPt=25+1.62520=57.5m/sv_P=v_0+a_Pt\\ =25+1.625*20=57.5\:\rm m/s

(iii)

dP=v0t+aPt2/2=2520+1.625202/2=825md_P=v_0t+a_Pt^2/2\\ =25*20+1.625*20^2/2=825\:\rm m


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