Question #320086

A particle at opposition r=I+ 2j+ 3k is acted upon by a force F 2= 4i +5j +6k.


Evaluate the torque experienced by the particle.

1
Expert's answer
2022-03-29T12:27:58-0400

The torque experienced by the particle

τ=r×F\vec \tau=\vec r\times \vec F

Hence

τ=(i^+2j^+3k^)×(4i^+5j^+6k^)=5k^6j^8k^+12i^+12j^15i^=3i^+6j^3k^\vec \tau=(\hat i+ 2\hat j+ 3\hat k)\times (4\hat i +5\hat j +6\hat k)\\ =5\hat k-6\hat j-8\hat k+12 \hat i+12 \hat j-15 \hat i\\ =-3\hat i+6\hat j-3\hat k


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