A particle at opposition r=I+ 2j+ 3k is acted upon by a force F 2= 4i +5j +6k.
Evaluate the torque experienced by the particle.
The torque experienced by the particle
"\\vec \\tau=\\vec r\\times \\vec F"Hence
"\\vec \\tau=(\\hat i+ 2\\hat j+ 3\\hat k)\\times (4\\hat i +5\\hat j +6\\hat k)\\\\\n=5\\hat k-6\\hat j-8\\hat k+12 \\hat i+12 \\hat j-15 \\hat i\\\\\n=-3\\hat i+6\\hat j-3\\hat k"
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