Answer to Question #319051 in Physics for percy

Question #319051

5. An electron has a kinetic energy of 6.4 X 10-19 J. What is this energy in electron volts?

 

6. Two metallic plates are 0.04 m apart and the potential difference between them is 50 V. Between the two equipotential surfaces, there is a potential difference of 2.5 V. Find the spacing in this part of the field between two metal plates.


1
Expert's answer
2022-03-27T18:20:57-0400

5.

6.41019J=4eV6.4*10^{-19}\:\rm J=4\:\rm eV

6. The electric field between plates

E=Vd=50V0.04m=1250V/mE=\frac{V}{d}=\frac{50\:\rm V}{0.04\:\rm m}=1250\:\rm V/m

The spacing between two surfaces

d=VE=2.5V1250V/m=0.002md'=\frac{V'}{E}=\frac{2.5\:\rm V}{1250\:\rm V/m}=0.002\:\rm m


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