Answer to Question #318696 in Physics for mcc

Question #318696

(a) Calculate the capacitance of a parallel-plate capacitor whose plates are 20 cm x 30 cm and are separated by a 1.0-mm air gap.


(b) what is the charge on each plate if a 12-V battery is connected across the two plates?


(c) What is the electric field between the plates?


1
Expert's answer
2022-03-27T10:56:04-0400

(a)

C=ϵ0Ad=8.8510120.20.30.001=5.311010FC=\frac{\epsilon_0 A}{d}\\ =\frac{8.85*10^{-12}*0.2*0.3}{0.001}=5.31*10^{-10}\:\rm F

(b)

q=CV=5.31101012=6.37109Cq=CV\\ =5.31*10^{-10}*12=6.37*10^{-9}\:\rm C

(c)

E=Vd=120.001=12000V/mE=\frac{V}{d}\\ =\frac{12}{0.001}=12000\:\rm V/m


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