Answer to Question #311933 in Physics for Dee

Question

A ball is thrown vertically upwards with an initial velocity of 30 m/s.

Using a time step of 0.02 s up to 6.20 s, plot the graph of the vertical distance versustime for this ball.

Hint ; Motion under gravity is described by the equation : 𝑣𝑦 = 𝑣𝑜𝑦𝑡 +1/2𝑔𝑡^2

and gravitational acceleration 𝑔 is here taken as negative.

NB:Show calculations for the answer.

(i) To what maximum height does the ball rise?(show calculations)

(ii) What is the index of time at maximum height(show calculations)

(iii) How long does it take the ball to ascend to maximum height?(show calculations)

(iv) How long does it take the ball to hit the ground?

(v) What happens to the ball if the sign for gravitational acceleration is taken as

Answer 1

(i) To what maximum height does the ball rise?

$$h_{\max}=46\:\rm m$$

(iii) How long does it take the ball to ascend to maximum height?

$$t_1=3\:\rm s$$

(iv) How long does it take the ball to hit the ground?

$$t_2=6.1\:\rm s$$

(v) What happens to the ball if the sign for gravitational acceleration is taken as positive?

It's velocity would increase.