Question #311834

A spherical-shaped capacitor has a charge equivalent to 4.45 nanocoulombs when connected to a battery that has a voltage of 220 V. Suppose the two shells of the spherical capacitor are 5.34 centimeters apart, what are the capacitance and the radius of the inner sphere?

1
Expert's answer
2022-03-15T10:34:37-0400

The capacitance is given by

C=qV=4.45109220=2.021011FC=\frac{q}{V}=\frac{4.45*10^{-9}}{220}=2.02*10^{-11}\:\rm F

On the other hand

C=4πϵ0(R2R1)/(R2R1)C=4\pi\epsilon_0(R_2*R_1)/(R_2-R_1)R2=R1+0.0534R_2=R_1+0.0534

So

2.021011=3.148.851012(R1+0.0534)R10.05342.02*10^{-11}=3.14*8.85*10^{-12}\frac{(R_1+0.0534)R_1}{0.0534}

(R1+0.0534)R1=0.0389(R_1+0.0534)R_1=0.0389

R1=0.172mR_1=0.172\:\rm m

R2=0.226mR_2=0.226\:\rm m


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