Question #285864

A flywheel is rotating at 30rev/s. What is the total angle in radians, through which a point on the flywheel rotates in 40 s? show the Given, Unknown, Equation and Solution

1
Expert's answer
2022-01-10T09:10:13-0500

Given: ω=30 revs\omega=30\ \dfrac{rev}{s} is angular velocity of the flywheel, t=40 st=40\ s is the time.

Unknown: θ\theta, the total angle in radians, through which a point on the flywheel rotates in t=40 st=40\ s.

Equation:


ω=θt.\omega=\dfrac{\theta}{t}.

Solution:


θ=ωt,\theta=\omega t,θ=30 revs×2π rad1 rev×40 s=7540 rad.\theta=30\ \dfrac{rev}{s}\times\dfrac{2\pi\ rad}{1\ rev}\times40\ s=7540\ rad.

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