Answer to Question #285864 in Physics for Junard

Question

A flywheel is rotating at 30rev/s. What is the total angle in radians, through which a point on the flywheel rotates in 40 s? show the Given, Unknown, Equation and Solution

Answer 1

Given: $\omega=30\ \dfrac{rev}{s}$ is angular velocity of the flywheel, $t=40\ s$ is the time.

Unknown: $\theta$, the total angle in radians, through which a point on the flywheel rotates in $t=40\ s$.

Equation:

$$\omega=\dfrac{\theta}{t}.$$

Solution:

$$\theta=\omega t,$$ $$\theta=30\ \dfrac{rev}{s}\times\dfrac{2\pi\ rad}{1\ rev}\times40\ s=7540\ rad.$$