Question #285809

A ball is moving at 18m/s in a direction inclined at 60°to the horizontal. The horizontal component of its velocity is?


1
Expert's answer
2022-01-10T09:09:47-0500

The horizontal component is


vx=vcos⁡60°=9 m/s.v_x=v\cos60°=9\text{ m/s}.


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