Question #280091

A pitcher throws a curveball that reaches the catcher in 0.14 s. The ball curves because it is spinning at an average angular velocity of 400 rev/min (assumed constant) on its way to the catcher's mitt. What is the angular displacement of the baseball (in radians) as it travels from the pitcher to the catcher?


Expert's answer

Let's first convert rev/min to rad/s:


ω=400 revmin×1 min60 s×2π rad1 rev=41.9 rads.\omega=400\ \dfrac{rev}{min}\times\dfrac{1\ min}{60\ s}\times\dfrac{2\pi\ rad}{1\ rev}=41.9\ \dfrac{rad}{s}.

Then, we can find the angular displacement of the baseball from the definition of angular velocity:


ω=ΔθΔt,\omega=\dfrac{\Delta\theta}{\Delta t},Δθ=ωΔt=41.9 rads×0.14 s=5.87 rad.\Delta\theta=\omega\Delta t=41.9\ \dfrac{rad}{s}\times0.14\ s=5.87\ rad.

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