Question #280091

A pitcher throws a curveball that reaches the catcher in 0.14 s. The ball curves because it is spinning at an average angular velocity of 400 rev/min (assumed constant) on its way to the catcher's mitt. What is the angular displacement of the baseball (in radians) as it travels from the pitcher to the catcher?


1
Expert's answer
2021-12-20T10:28:59-0500

Let's first convert rev/min to rad/s:


ω=400 revmin×1 min60 s×2π rad1 rev=41.9 rads.\omega=400\ \dfrac{rev}{min}\times\dfrac{1\ min}{60\ s}\times\dfrac{2\pi\ rad}{1\ rev}=41.9\ \dfrac{rad}{s}.

Then, we can find the angular displacement of the baseball from the definition of angular velocity:


ω=ΔθΔt,\omega=\dfrac{\Delta\theta}{\Delta t},Δθ=ωΔt=41.9 rads×0.14 s=5.87 rad.\Delta\theta=\omega\Delta t=41.9\ \dfrac{rad}{s}\times0.14\ s=5.87\ rad.

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