Answer to Question #280087 in Physics for Faith

Question

A crane has an arm length of 20 m inclined at 30deg with the vertical. It carries a container of mass of 3 ton suspended from the top end of the arm. Find the torque produced by the gravitational force on the container about the point where the arm is fixed to the crane. Given: 1 ton = 1000 kg; neglect the weight of the arm. Hint: take the force and perpendicular distance from the point where the arm is fixed to the crane.

Answer 1

The torque produced by the gravitational force on the container about the point where the arm is fixed to the crane:

$$T=mgd\sin\theta=294000\text{ N}·\text m.$$