Answer to Question #280026 in Physics for angel

Question #280026

A 210-kg spacecraft crash-landed on a desert with a velocity of 311 kph and ended up 0.810 m underneath the soil.

a. Draw a free-body diagram for the spacecraft.

b. Determine the spacecraft’s velocity in m/s.

c. Solve the spacecraft’s acceleration

d. Determine the force the ground exerted on the spacecraft during the crash landing

e. Solve the duration of the crash


1
Expert's answer
2021-12-16T11:34:08-0500

Velocity:


v=3111000/3600=86.4 m/s.v=311·1000/3600=86.4\text{ m/s}.

Acceleration:


a=v2/(2d)=4608 m/s2.a=v^2/(2d)=4608\text{ m/s}^2.

Force:


F=ma=967680 N.F=ma=967680\text{ N}.

Duration:


t=v/a=0.02 s.t=v/a=0.02\text{ s}.


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