Answer to Question #280026 in Physics for angel

Question

A 210-kg spacecraft crash-landed on a desert with a velocity of 311 kph and ended up 0.810 m underneath the soil.

a. Draw a free-body diagram for the spacecraft.

b. Determine the spacecraft’s velocity in m/s.

c. Solve the spacecraft’s acceleration

d. Determine the force the ground exerted on the spacecraft during the crash landing

e. Solve the duration of the crash

Answer 1

Velocity:

$v=311·1000/3600=86.4\text{ m/s}.$

Acceleration:

$a=v^2/(2d)=4608\text{ m/s}^2.$

Force:

$F=ma=967680\text{ N}.$

Duration:

$t=v/a=0.02\text{ s}.$