Question #279439

In a car lift used in a service station, compressed air exerts a force on a small piston having a radius of 1.5 cm. This pressure is transmitted to a second piston of radius of 6.75 cm. What force must the compressed air exert in order to lift a car weighing 17,750 Newton’s? What air pressure will produce this force?

1
Expert's answer
2021-12-20T10:29:23-0500

The forces and pistons' areas are connected as follows:


F2=F1A2A1F_2 = \dfrac{F_1A_2}{A_1}

where F2,F1=17750NF_2, F_1 = 17750N are the forces exerted by the second and first pistons respectively, A2,A1A_2, A_1 are their areas. Since areas are proportional to the radii squared (r1=1.5cm,r2=6.75cmr_1 = 1.5cm, r_2 = 6.75cm), obtain:


F2=F1r22r12=17750N(1.5cm)2(6.45cm)29.6×102NF_2 = \dfrac{F_1r_2^2 }{r_1^2} = \dfrac{17750N\cdot (1.5cm)^2}{(6.45cm)^2} \approx 9.6\times 10^2N

Answer. 9.6×102N9.6\times 10^2N.


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