Calculate the mass of a solid iron sphere that has a diameter of 3.0 cm.
m=ρ⋅V=ρ⋅43⋅π⋅r3=7874⋅43⋅3.14⋅0.033=m=\rho\cdot V=\rho\cdot\frac{4}{3}\cdot\pi\cdot r^3=7874\cdot\frac{4}{3}\cdot3.14\cdot 0.03^3=m=ρ⋅V=ρ⋅34⋅π⋅r3=7874⋅34⋅3.14⋅0.033=
=0.89 (kg)=890 (g)=0.89\ (kg)=890\ (g)=0.89 (kg)=890 (g) . Answer
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