Question #277576

A particle whose mass is 3 kg moves in the xy plane with velocity along the


line y=5.3 m.


(a) Find the angular momentum about the origin when the particle is at (12 m, 5.3 m).


(b) A force is applied to the particle. Find the torque about the origin due to


this force as the particle passes through the point (12 m, 5.3 m).

Expert's answer

(a) The angular momentum:


L=pr=mvx=36v kgm2/s.L=pr=mvx=36v\text{ kg}·\text{m}^2/\text s.

(b) The torque:


T=Fd=12F N.T=Fd=12F\text{ N}.


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