The uniform bar of length L 40 N and is subjected to four forces shown. Find the
magnitude, location and direction of a fifth force F needed to keep the bar in equilibrium.
We have two forces of 4 N pushing down at equal distance from the pivot point and a force of 4 N on the left and 2 N on the right. Therefore, since all forces and torques must be in equilibrium, the value of the fifth force is 2 N upward at the point where he 2-N force is applied.
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