Answer to Question #276980 in Physics for Ahanaf

Question

A person is jumping from a height h0 = 10 m with zero initial velocity and a cricket ball is thrown directly upward with an initial velocity v0 = 9.8 m/s at the same instant when time t = 0 s as shown in Fig. 1. Consider h = 11.5 m and i and j to be the unit vectors along the X and Y axis. Gravity is acting along the j direction and the magnitude of gravitational acceleration is given by g = 9.81 m/s2 . The red dot on the person represents his center of mass.

(b) If it takes 0.01 seconds for the person to come to complete rest when he hits the ground, calculate the average force acting on the person

Answer 1

$$mv=Ft\\m\sqrt{2gh}=Ft\\60\sqrt{2(9.81)(10)}=0.01F\\F=84\ kN$$