Answer to Question #275280 in Physics for marie

Question

Water at room temperature flows with a constant speed of 8.00 m/s through a nozzle with a square cross section, as shown in the figure. Water enters the nozzle at the point A and exits the nozzle at point B. The length of the sides of the square cross section at A and B are 50.0 cm and 20.0 cm, respectively.

a. What is the volume flow rate at the exit?

b. What is the acceleration at the exit? The length of the nozzle is 2.00 m.

c. If the volume flow rate through the nozzle is increased to 6.00 m3/s, what is the acceleration of the fluid at the exit?

Answer 1

$$Q=(0.5)(0.2)(8)=0.8\frac{m^3}{s}\\8^2=2(2)a\\a=16\frac{m}{s^2}\\\\a'=16\frac{6}{0.8}=120\frac{m}{s^2}$$