Question #275271

1. Renz is approaching a stoplight moving with a velocity of +30.0 m/s. The light turns yellow, and Renz applies the brakes and skids to a stop. If Renz acceleration is -8.00 m/s2, then determine the displacement of the car during the skidding process.

2. A car slows down its motion from 10 m/s to 6 m/s in 2 seconds under constant acceleration. What is its acceleration?

3. A car starts its motion from rest and uniformly accelerates at a rate of 4 m/s2 for 2 seconds in a straight line. How far did the car travel during those 2 seconds?

4. An object, without change in direction, travels a distance of 50 m with an initial speed of 5 m/s in 4 s. Find the object's velocity at the end of the given time interval? 

5. Ben Simmons is waiting at a stoplight. When it finally turns green, Ben accelerated from rest at a rate of 6.00 m/sfor a time of 4.10 seconds. Determine the displacement of Ben's car during this time period.



 

 

 

 

 

 

 

 

 

 



1
Expert's answer
2021-12-06T09:42:40-0500

1)

v2=v02+2ad,v^2=v_0^2+2ad,0=v02+2ad,0=v_0^2+2ad,d=v022a=(30 ms)22×(8 ms2)=56.25 m.d=-\dfrac{v_0^2}{2a}=-\dfrac{(30\ \dfrac{m}{s})^2}{2\times(-8\ \dfrac{m}{s^2})}=56.25\ m.

2)

v=v0+at,v=v_0+at,a=vv0t=6 ms10 ms2 s=2 ms.a=\dfrac{v-v_0}{t}=\dfrac{6\ \dfrac{m}{s}-10\ \dfrac{m}{s}}{2\ s}=-2\ \dfrac{m}{s}.

3)

d=v0t+12at2,d=v_0t+\dfrac{1}{2}at^2,d=0+12×4 ms2×(2 s)2=8 m.d=0+\dfrac{1}{2}\times4\ \dfrac{m}{s^2}\times(2\ s)^2=8\ m.

4)

d=12(v0+v)t,d=\dfrac{1}{2}(v_0+v)t,v=2dtv0=2×50 m4 s5 ms=20 ms.v=\dfrac{2d}{t}-v_0=\dfrac{2\times50\ m}{4\ s}-5\ \dfrac{m}{s}=20\ \dfrac{m}{s}.

5)

d=v0t+12at2,d=v_0t+\dfrac{1}{2}at^2,d=0+12×6 ms2×(4.1 s)2=50.43 m.d=0+\dfrac{1}{2}\times6\ \dfrac{m}{s^2}\times(4.1\ s)^2=50.43\ m.

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