Question #271371

1.     A 700.0-N sign hangs from the end of a uniform strut. The strut is 4.0 m long and weighs 800.0 N. The strut is supported by a hinge at the wall and by a cable whose other end is tied to the wall at a point 3.0 m above the left end of the strut. Find the tension in the supporting cable and the force of the hinge on the strut.




Expert's answer

35T=600+400T=1667 N\frac{3}{5}T=600+400\\T=1667\ N

F=451667=1333 NF=\frac{4}{5}1667=1333\ N


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