Answer to Question #270414 in Physics for haze

Question #270414

If you add 600 cal of heat to 50 g of water at 10oC, what will be the temperature of the water in oC?

Expert's answer

"600\\ cal=2510.4\\ J"

"Q=cm(t-t_0)\\to t=Q\/(cm)+t_0=2510.4\/(4182\\cdot0.05)+10=22\u00b0C" . Answer

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