Question #270414

If you add 600 cal of heat to 50 g of water at 10oC, what will be the temperature of the water in oC?

1
Expert's answer
2021-11-23T10:31:24-0500

600 cal=2510.4 J600\ cal=2510.4\ J


Q=cm(t−t0)→t=Q/(cm)+t0=2510.4/(4182⋅0.05)+10=22°CQ=cm(t-t_0)\to t=Q/(cm)+t_0=2510.4/(4182\cdot0.05)+10=22°C . Answer

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