Answer to Question #270413 in Physics for haze

Question

Work of 500 J is done by an ideal gas, when 500 cal of heat is added to the gas. What is the increase in the internal energy of the gas in J?

Answer 1

$500\ cal=2092\ J$

$Q=\Delta U+W\to \Delta U=Q-W=2092-500=1592\ (J)$ . Answer