Answer to Question #270413 in Physics for haze

Question #270413

Work of 500 J is done by an ideal gas, when 500 cal of heat is added to the gas. What is the increase in the internal energy of the gas in J?

Expert's answer

"500\\ cal=2092\\ J"

"Q=\\Delta U+W\\to \\Delta U=Q-W=2092-500=1592\\ (J)" . Answer

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