Question #268073

A galvanometer of resistor 10 ohms gives a full scale deflection when a current of 50amphere flow through it.

How can it be converted to an ammeter to measure a current of 5Amphere?

How can it be converted to a voltmeter to measure a voltage of 3volts?


Expert's answer

(a) Ammeter


A galvanometer can function as an ammeter when it is placed in parallel with a small resistance RR .


IR=IGr→R=IGIr=0.0000055−0.000005⋅10=1⋅10−5 (Ω)IR=I_Gr\to R=\frac{I_G}{I}r=\frac{0.000005}{5-0.000005}\cdot 10=1\cdot10^{-5} \ (\Omega)


(b) Voltmeter


A galvanometer can function as a voltmeter when it is connected in series with a large resistance RR .

Rtotal=R+r=V/I=3/(50⋅10−6)=60000 (Ω)R_{total}=R+r=V/I=3/(50\cdot10^{-6})=60000\ (\Omega)


R=Rtotal−r=60000−10=59990 (Ω)R=R_{total}-r=60000-10=59990\ (\Omega)










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