Calculate electric field intensity due to a spherical charge distribution given as ρ(x)=ρ°{1-(x²/R²)} , x≤R
And ρ(x)=0; x>R at external point, at surface and at internal point.
"\\rho=dq\/dV\\to q(x)=\\int\\rho dV=4\\pi\\rho_0(x^3\/3-x^5\/(5R^2))"
"\\int EdA=q\/\\epsilon_0" . So, we have
"E=(\\rho_0\/\\epsilon_0)\\cdot(x\/3-x^3\/(5R^2))\\ \\ \\ x\\leq R"
"E=(\\rho_0\/\\epsilon_0)(2R^3\/(15x^2))\\ \\ \\ x> R"
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