. The temperature of an ideal gas increases from 20 ̊C to 40 ̊C while the pressure stays the same. What happens to the volume of the gas?
pV1/T1=pV2/T2→V1T2=V2T1→pV_1/T_1=pV_2/T_2\to V_1T_2=V_2T_1\topV1/T1=pV2/T2→V1T2=V2T1→
V2/V1=T2/T1=(273+40)/(273+20)=1.068V_2/V_1=T_2/T_1=(273+40)/(273+20)=1.068V2/V1=T2/T1=(273+40)/(273+20)=1.068
The volume will increase 1.068 times.
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