Question #265197

A particle moves from x1 = 5 cm to x2 = 20 cm in 5 s. The average velocity of the particle during this time interval is


1
Expert's answer
2021-11-14T17:18:20-0500
vavg=ΔxΔt=0.2 m0.05 m5 s=0.03 ms=3 cms.v_{avg}=\dfrac{\Delta x}{\Delta t}=\dfrac{0.2\ m-0.05\ m}{5\ s}=0.03\ \dfrac{m}{s}=3\ \dfrac{cm}{s}.

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