Question #265076

The deepest point in the ocean is in the Mariana Trench, about 11 km deep, in the Pacific. The pressure at this depth is huge, about 1.13 x 10^8 Pa. (a) Calculate the change in volume of 1.00 m3 of seawater carried from the surface to this deepest point. (b) The density of seawater at the surface is 1.03 x 10^3 kg/m3. Find its density at the bottom. (c) Explain whether or when it is a good approximation to think of water as incompressible.

1
Expert's answer
2021-11-14T17:17:00-0500

a) β=1V(ΔVΔp)ΔV=βVΔp=\beta=-\frac{1}{V}\cdot(\frac{\Delta V}{\Delta p})\to \Delta V=-\beta V\cdot\Delta p=


=0.5110911.13108=0.05763 (m3)=-0.51\cdot10^{-9}\cdot1\cdot1.13\cdot10^8=-0.05763\ (m^3)


b) ρh=m/Vh=1030/(10.05763)=1093 (kg/m3)\rho_h=m/V_h=1030/(1-0.05763)=1093\ (kg/m^3)


c) Since the coefficient of volumetric compression of water is β=0.51109 (Pa1)\beta=0.51\cdot10^{-9}\ (Pa^{-1}) , it is a good approximation to think of water as incompressible.




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