Question #264974

A constant torque of 35 m∙N is applied to a wheel with a moment of inertia of 1.5 kg∙m2. (a) Find the angular acceleration.

(b) Find also the angular speed at the end of 25s, assuming the wheel starts from rest. Show your complete solution.


1
Expert's answer
2021-11-15T10:33:42-0500

(a) The angular acceleration is


α=TI=23.3 rad/s.\alpha=\frac TI=23.3\text{ rad/s}.

(b) The angular speed is

ω=12αt2=1223.3252=7281 rad/s.\omega=\frac12\alpha t^2=\frac12·23.3·25^2=7281\text{ rad/s}.


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