Question #264974

A constant torque of 35 m∙N is applied to a wheel with a moment of inertia of 1.5 kg∙m2. (a) Find the angular acceleration.

(b) Find also the angular speed at the end of 25s, assuming the wheel starts from rest. Show your complete solution.


Expert's answer

(a) The angular acceleration is


α=TI=23.3 rad/s.\alpha=\frac TI=23.3\text{ rad/s}.

(b) The angular speed is

ω=12αt2=1223.3252=7281 rad/s.\omega=\frac12\alpha t^2=\frac12·23.3·25^2=7281\text{ rad/s}.


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