Answer to Question #264330 in Physics for Lhen

Question #264330

A cliff is 22 meters high.You fell in the water 5 meters away from the hil.What is your initial horizontal velocity


1
Expert's answer
2021-11-11T09:32:13-0500

The time tt of free fall (assuming no initial vertical velocity) can be found from kinematic equation:


h=gt22t=2hgh = \dfrac{gt^2}{2}\\ t = \sqrt{\dfrac{2h}{g}}

where h=22mh = 22m is the height of the cliff, and g=9.8m/s2g = 9.8m/s^2 is the gravitational acceleration.

Since the horizontal velocity does not changes, its initial value is:


v=dt=dg2hv = \dfrac{d}{t} = d\sqrt{\dfrac{g}{2h}}

where d=5md = 5m is the horizontal range. Thus, obtain:


v=dg2h=5m9.8m/s2222m2.4m/sv = d\sqrt{\dfrac{g}{2h}} =5m\cdot \sqrt{\dfrac{9.8m/s^2}{2\cdot 22m}} \approx 2.4m/s

Answer. 2.4 m/s.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment